Particular solution for sin using complex exponentials YouTube
Exponential Form Of Sin. Sin z = exp(iz) − exp(−iz) 2i sin z = exp ( i z) − exp ( − i z) 2 i. For any complex number z z :
Sin z = exp(iz) − exp(−iz) 2i sin z = exp ( i z) − exp ( − i z) 2 i. For any complex number z z :
Sin z = exp(iz) − exp(−iz) 2i sin z = exp ( i z) − exp ( − i z) 2 i. Sin z = exp(iz) − exp(−iz) 2i sin z = exp ( i z) − exp ( − i z) 2 i. For any complex number z z :
